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Add filter site__user_in on wp site list #438

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Merged
merged 9 commits into from
Feb 6, 2024
Merged

Add filter site__user_in on wp site list #438

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5cfa326
Add filter site__user_in on wp site list
marksabbath Nov 11, 2023
d00d7d6
Return error if cannot find a site
marksabbath Nov 11, 2023
e08c6e4
Update src/Site_Command.php
marksabbath Nov 13, 2023
399c882
Change filter to user__in
marksabbath Nov 13, 2023
6da4e66
Update flag name and output blank list when none found
marksabbath Feb 5, 2024
f30bbee
Fix spaces in =
marksabbath Feb 5, 2024
23bcdcb
Update flag name to site_user
marksabbath Feb 5, 2024
b016207
Add a test for the zero sites state
danielbachhuber Feb 6, 2024
d81fa62
Update README
danielbachhuber Feb 6, 2024
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Add filter site__user_in on wp site list
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@marksabbath
marksabbath committed Nov 11, 2023
commit 5cfa326af47db102bb2c84e02d3251f9d05aa21f
20 changes: 20 additions & 0 deletions features/site.feature
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Original file line number Diff line number Diff line change
Expand Up @@ -98,6 +98,26 @@ Feature: Manage sites in a multisite installation
{SCHEME}://example.com/first/
"""

Scenario: Filter site list by user
Given a WP multisite install

When I run `wp site create --slug=first --porcelain`
Then STDOUT should be a number
And save STDOUT as {SITE_ID}
And I run `wp site list --site__in={SITE_ID} --field=url`
And save STDOUT as {SITE_URL}
And I run `wp user create newuser newuser@example.com --porcelain --url={SITE_URL}`
Then STDOUT should be a number
And save STDOUT as {USER_ID}
And I run `wp user get {USER_ID} --field=user_login`
And save STDOUT as {USER_LOGIN}

When I run `wp site list --field=url --site__user_in={USER_LOGIN}`
Then STDOUT should be:
"""
{SITE_URL}
"""

Scenario: Delete a site by slug
Given a WP multisite install

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18 changes: 17 additions & 1 deletion src/Site_Command.php
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Expand Up @@ -520,7 +520,10 @@ private function get_network( $network_id ) {
* 'url' isn't an available filter, as it comes from 'home' in wp_options.
*
* [--site__in=<value>]
* : Only list the sites with these blog_id values (comma-separated).
* : Only list 1 the sites with these blog_id values (comma-separated).
*
* [--site__user_in=<value>]
* : Only list the sites with this user.
*
* [--field=<field>]
* : Prints the value of a single field for each site.
Expand Down Expand Up @@ -607,6 +610,19 @@ public function list_( $args, $assoc_args ) {
$where['site_id'] = $assoc_args['network'];
}

if ( isset( $assoc_args['site__user_in'] ) ) {
$user = get_user_by( 'login', $assoc_args['site__user_in'] );
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@danielbachhuber danielbachhuber Nov 13, 2023

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_in implies the argument supports a CSV of users. Should we accommodate that here?

Also, we should use WP_CLI\Fetchers\User instead of directly calling get_user_by(). It will handle the "invalid user" case for us.

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@marksabbath marksabbath Nov 13, 2023

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Il'll take a look at WP_CLI\Fetchers\User.

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@marksabbath marksabbath Feb 5, 2024

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I've updated the code to use WP_CLI\Fetchers\User and also updated the name of the flag to --user.

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@marksabbath marksabbath Feb 5, 2024

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@danielbachhuber I needed to change the flag to site_user since it was not properly working with user. I guess it conflicts with some global flag or something.

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@danielbachhuber danielbachhuber Feb 6, 2024

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I needed to change the flag to site_user since it was not properly working with user. I guess it conflicts with some global flag or something.

@marksabbath Yep, it does. site_user is a fine alternative.


if ( $user ) {
$blogs = get_blogs_of_user( $user->id );

foreach( $blogs as $blog ) {
$where['blog_id'][] = $blog->userblog_id;
}
$append = 'ORDER BY FIELD( blog_id, ' . implode( ',', array_map( 'intval', $where['blog_id'] ) ) . ' )';
}
}

$iterator_args = [
'table' => $wpdb->blogs,
'where' => $where,
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